A horse traveled at a constant speed of ^@30 \space km/h ^@ for the initial ^@2^@ hours and then at a constant speed of ^@20 \space km/h^@ for ^@3^@ hours. What was its average speed?
Answer:
^@24 \space km/h^@
- Given, speed for the initial ^@2^@ hours ^@= 30 \space km/h ^@
Speed for the remaining ^@3^@ hours ^@ = 20 \space km/h^@
So, the total time of the journey ^@ = 2 + 3 = 5^@ hours
Average speed can be found by using the formula below:
Average speed ^@ = ^@ Total distance ^@\div^@ Total time Distance covered in the initial ^@ 2 ^@ hours ^@ = 2 \times 30 ^@ ^@ = 60 \space km. ^@ Distance covered in the remaining ^@ 3 ^@ hours ^@ = 3 \times 20 ^@ ^@ = 60 \space km. \space\space\space\space ^@ Total distance covered ^@ = 60 + 60 ^@ ^@ = 120 \space km. ^@ Average speed ^@ = 120 \div 5 ^@ ^@ = 24 \space km/h. ^@ - Hence, the average speed of the horse was ^@24 \space km/h^@.