A number is increased by 40% and then the increased number is decreased by 40%. Find the net increase or decrease percent.
Answer:
16%
- Let the number be x.
We are given that a number is increased by 40%.
So, increased percentage = (100+40)% = 140%
Then, Increased number = 140% of x=(140100×x)=75x Now, the number is decreased by 40%. So, the decreased number will be (100−40)% = 60% of the increased number. Decreased number = 60% of 75x=(60100×75x)=420500x∴ Net decrease = Original Number - Decreased Number =(x−420500x)=80500x - Therefore, Net decrease %= Net decrease Original number ×100%=(80x500÷x×100)%=(80x500×1x×100)%=16% Hence, the net decrease is 16%.