If A, B, and C are the angles of ΔABC, show that cot(B+C2) = tan(A2).


Answer:


Step by Step Explanation:
  1. We know that the sum of the angles of a triangle is 180.  A+B+C=180B+C2=90A2cot(B+C2)=cot(90A2)cot(B+C2)=tanA2[ cot(90θ)=tanθ ]
  2. Thus, cot(B+C2)=tanA2.

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