In ΔABC, AD⊥BC and AD2=BD×CD. Prove that ∠BAC=90∘.
Answer:
- Given:
AD⊥BC and AD2=BD×CD
Here, we have to find the value of ∠BAC. - Now, we have: AD2=BD×CD⟹BDAD=ADCD
Now, in ΔDBA and ΔDAC, we have
∠BDA=∠ADC=90∘ and BDAD=ADCD∴