In a rectangle ABCD, the diagonals bisect at O. What kind of a triangle AOB is?
Answer:
an isosceles but not right angled triangle
- Following figure shows the rectangle ABCD with diagonals.
- We know that diagonals of a rectangle are equal and bisects each other, therefore
AC = BD
⇒ AC/2 = BD/2
⇒ AO = OB
Also, ∠AOC ≠ 90° .... (since diagonals are not perpendicular) - Since AO = OB and ∠AOC ≠ 90° , triangle ΔAOB is an isosceles but not right angled triangle.